X^2+5x-6=0 ///////help
x₁ =1 корень ⇒x₂ = (-6) /1 = -6 (Виет ) x²+5x-6=0 ⇔x²- x +6x -6=0⇔ x(x-1)- +6(x -1)=0 ⇔(x-1)(x+6) =0
D = 5² - 4*1*(-6) = 25 + 24 = 49, D > 0, x1 = (-5 + 7) / 2 = 2/2 = 1. x2 = (-5 - 7) / 2 = -12 / 2 = -6.
thanks
ne za chto.