Решить в 1.203 А,Е

$(\sqrt{20}+\sqrt{5})^2=(\sqrt{4\cdot 5}+\sqrt{5})^2=(2\sqrt{5}+\sqrt{5})^2= (3\sqrt{5})^2=9\cdot 5=45$

$(\sqrt{0,18}+\sqrt{0,08})^2=\left(\sqrt{\frac{9\cdot 2}{100}}+\sqrt{\frac{4\cdot 2}{100}}\right)^2=\left(\frac{3\sqrt{2}}{10}+\frac{2\sqrt{2}}{10}\right)^2= \left(\frac{5\sqrt{2}}{10}\right)^2=$

$=\left(\frac{\sqrt{2}}{2}\right)^2=\frac{2}{4}=\frac{1}{2}=0,5$

Ответ: а) 45; е) 0,5