(x-2)(x+2)-3x+(4-x)²+2
(x - 2)(x + 2) - 3x + (4 - x)² + 2 = x² - 4 - 3x + 16 - 8x + x² + 2 = 2x² - 11x + 14 =
= 2(x - 3,5)(x - 2) = (2x - 7)(x - 2);
2x² - 11x + 14 = 0 D = b²-4ac = 121-112 = 9
x₁ = (-b+√D)/2a = (11+3)/4 = 3,5
x₂ = (-b -√D)/2a = (11-3)/4 = 2