Плиз решите А и Г СРОЧНО!!!!

Решите задачу:

$\displaystyle\tt 1) \ \ \frac{4^8\cdot9^7+6^{12}\cdot180}{8^6\cdot3^{14}-6^{14}}= \frac{2^{16}\cdot3^{14}+3^{12}\cdot2^{12}\cdot5\cdot2^2\cdot3^2}{2^{18}\cdot3^{14}-2^{14}\cdot3^{14}}=\\\\\\=\frac{2^{16}\cdot3^{14}+3^{14}\cdot2^{14}\cdot5}{3^{14}\cdot2^{14}(2^{4}-1)}=\frac{3^{14}\cdot2^{14}(2^{2}+5)}{3^{14}\cdot2^{14}(2^{4}-1)}=\frac{4+5}{16-1}=\frac{9}{15}=\frac{3}{5}$

$\displaystyle\tt 2) \ \ \frac{21(3\cdot7^{12}-14\cdot7^{11})}{(3\cdot7^6)^2}=\frac{3\cdot7(3\cdot7^{12}-2\cdot7^{12})}{3^2\cdot7^{12}}= \frac{7^{12}(3-2)}{3\cdot7^{11}}=\frac{7}{3}$