Решите неравенство:log(3)*(log1/3*x/1-x)<=3

По условию (заказчика на самом деле стоит не 3 а 0 в правой части)

$log_3 (log_{\frac{1}{3}}( \frac{x}{1-x}) \leq 0$
1" alt="3>1" align="absmiddle" class="latex-formula">
$0<log_{\frac{1}{3}} \frac{x}{1-x} \leq 3^0$
$0<log_{\frac{1}{3}} \frac{x}{1-x} \leq 1$
$0<\frac{1}{3}<1$
\frac{x}{1-x} \geq (\frac{1}{3})^1" alt="(\frac{1}{3})^0>\frac{x}{1-x} \geq (\frac{1}{3})^1" align="absmiddle" class="latex-formula">
\frac{1}{1-x}-1 \geq \frac{1}{3}" alt="1>\frac{1}{1-x}-1 \geq \frac{1}{3}" align="absmiddle" class="latex-formula">
\frac{1}{1-x} \geq \frac{5}{3}" alt="2>\frac{1}{1-x} \geq \frac{5}{3}" align="absmiddle" class="latex-formula">
$\frac{1}{2}<1-x \leq \frac{3}{5}$
$-\frac{1}{2}<-x \leq -\frac{2}{5}$
x \geq \frac{2}{5}" alt="\frac{1}{2} >x \geq \frac{2}{5}" align="absmiddle" class="latex-formula">
х є $[0.4;0.5)$