x + y = 3 , xy = 7
a) x²y + xy² = xy * (x + y) = 7 * 3 = 21
в) x² + y² = (x + y)² - 2xy = 3² - 2 * 7 = 9 - 14 = - 5
г) x³ + y³ = (x + y)*(x² - xy + y²) = (x + y)[(x + y)² - 2xy - xy] = (x + y)[(x + y)² - 3xy] =
= 3 * (3² - 3 * 7) = 3 * (9 - 21) = 3 * (- 12) = - 36