25-[2+5y-3(y+2)]=3(2y-5)-[5(y-1)-3y+3]
25-(2+5у-3(у+2))=3(2у-5)-(5(у-1)-3у+3) 25-(2+5у-3у-6)=6у-15-(5у-5-3у+3) 25-(2у-4)=6у-15-(2у-2) 25-2у+4=6у-15-2у+2 -6у=-15+2-25-4 -6у=-42 у=7