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$1)\; \; 1-\frac{5}{8}=\frac{8}{8}-\frac{5}{8}=\frac{3}{8}\\\\3\frac{3}{10}-1\frac{7}{15}=\frac{33}{10}-\frac{22}{15}=\frac{33\cdot 3-22\cdot 2}{10\cdot 3}=\frac{55}{30}=\frac{11}{6}=1\frac{5}{6}\\\\10-1\frac{1}{9}=10-\frac{10}{9}=\frac{90-10}{9}=\frac{80}{9}=8\frac{8}{9}\\\\7\frac{5}{18}-1\frac{7}{12}=\frac{131}{18}-\frac{19}{12}=\frac{131\cdot 2-19\cdot 3}{18\cdot 2}=\frac{205}{36}=5\frac{25}{36}\\\\9\frac{5}{6}-2\frac{3}{4}=\frac{59}{6}-\frac{11}{4}=\frac{59\cdot 2-11\cdot 3}{6\cdot 2}=\frac{85}{12}=7\frac{1}{12}$

$5\frac{3}{24}-1\frac{1}{21}=\frac{123}{24}-\frac{22}{21}=\frac{123\cdot 7-22\cdot 8}{24\cdot 7}=\frac{685}{168}=4\frac{13}{168}\\\\2)\; \; 12\frac{5}{12}+4\frac{1}{8}-4\frac{2}{3}=\frac{149}{12}+\frac{33}{8}-\frac{14}{3}=\frac{149\cdot 2+33\cdot 3-14\cdot 8}{12\cdot 2}=\frac{285}{24}=11\frac{7}{8}\\\\5\frac{9}{10}+5-2\frac{8}{15}=\frac{59}{10}+\frac{150}{30}-\frac{38}{15}=\frac{251}{30}=8\frac{11}{30}\\\\3)\; \; 84,5\cdot \frac{0,8}{100}=0,676\; ;\; \; \frac{5}{18}\cdot \frac{63}{100}=0,175$

$\frac{4,2}{100}\cdot 24,5=1,029\; \; ,\; \; \frac{6}{11}\cdot \frac{66}{100}=0,36\\\\0,18\cdot 1\frac{5}{9}=\frac{18}{100}\cdot \frac{14}{9}=0,28\\\\1\frac{1}{9}\cdot 12,6=\frac{10}{9}\cdot \frac{126}{10}=14\\\\0,56\cdot 3\frac{1}{8}=\frac{56}{100}\cdot \frac{25}{8}=1,75\\\\2\frac{1}{7}\cdot 1,54=\frac{15}{7}\cdot \frac{154}{100}=3,3$