Помогите 2,3 найти значение выражения

Решите задачу:

$x \times {6}^{4x - 5} \times {36}^{3 - 2x} = x \times {6}^{4x - 5} \times {6}^{2(3 - 2x) }= x \times {6}^{4x - 5} \times {6}^{6 - 4x} = x \times {6}^{4x - 5 + 6 - 4x} = x \times 6 = 8 \times 6 = 48$
$x \div {2}^{2x + 3} \times {4}^{x - 2} = x \div {2}^{2x + 3} \times {2}^{2(x - 2)} = x \div {2}^{2 x + 3} \times {2}^{2x - 4} = x \times {2}^{2x - 4 - 2x - 3} = x \times {2}^{ - 7} = 64 \times \frac{1}{128} = \frac{1}{2}$