2log5 x+log5 100−2=0
2log5 (x) + log5 (100) - 2 = 0 log5 (x^2) + log5 (100) = 2 log5 (x^2*100) = 2 x^2*100 = 25 x^2 = 0,25 x = ±0,5 ОДЗ х>0, поэтому х = 0,5
2 log(5)x+log(5)100-2=0 ;x>0 2log(5)x+2 log(5)10-2=0 log(5)х+log(5)10-1=0 log(5)x+log(5)2+log(5)5-1=0 log(5)x+log(5)2=0 log(5)x=-log(5)2 ĺog(5)x=log(5)2^(-1) x=1/2