Решите систему пожалуйста

${(x + 4)}^{2} - {(x + 2)}^{2} = 2y + 23 \\ {(y + 5)}^{2} - {(y + 1)}^{2} = 6x + 15 \\ \\ (x + 4 + x + 2)(x + 4 - x - 2) = 2y + 23 \\ (y + 5 + y + 1)(y + 5 - y - 1) = 6x + 15 \\ \\ (2x + 6) \times 2 = 2y + 23 \\ (2y + 6) \times 4 = 6x + 15 \\ \\ 4x + 12 = 2y + 23 \\ 8y + 24 = 6x + 15 \\ \\ 4x - 2y = 11 \\ 6x - 8y = 9 \\ \\16x - 8y = 44 \\ 6x - 8y = 9 \\ \\ 10x = 35 \\ y = \frac{4x - 11}{2} \\ \\ x = 3.5 \\ y = 1.5$
Ответ: (3,5; 1,5)