0\\5a^2-a-6=0\\a_{1,2}=\frac{1^+_-11}{10}\\a_1=\frac{6}{5}\ a_2=-1(a\in\varnothing)\\\frac{5}{2}^x=\frac{6}{5}\\x=log_\frac{5}{2}\frac{6}{5}\approx0,2\\.+[log_\frac{5}{2}\frac{6}{5}]-(0,5)+>x\\OTBET:x\in[log_\frac{5}{2}\frac{6}{5};0,5) " alt=" \frac{2*5^{2x+1}-10^x-6*4^x-25}{25^x-5}\leq5\\\frac{2*5^{2x+1}-10^x-6*4^x-25-5*5^{2x}+25}{25^x-5}\leq0\\\frac{5^{2x+1}-10^x-6*4^x}{25^x-5}\leq0\\.*)5^{2x+1}-10^x-6*4^x=0|:4^x\\5*\frac{5}{2}^{2x}-\frac{5}{2}^x-6=0\\\frac{5}{2}^x=a;a>0\\5a^2-a-6=0\\a_{1,2}=\frac{1^+_-11}{10}\\a_1=\frac{6}{5}\ a_2=-1(a\in\varnothing)\\\frac{5}{2}^x=\frac{6}{5}\\x=log_\frac{5}{2}\frac{6}{5}\approx0,2\\.+[log_\frac{5}{2}\frac{6}{5}]-(0,5)+>x\\OTBET:x\in[log_\frac{5}{2}\frac{6}{5};0,5) " align="absmiddle" class="latex-formula">