-(3/12)log2(3/12)-(3/12)log2(3/12)-(6/12)log2(6/12)=? я знаю ответ. Подскажите подробный...

$- \frac{3}{12} log_{2}( \frac{3}{12} ) - \frac{3}{12} log_{2}( \frac{3}{12} ) - \frac{6}{12} log_{2}( \frac{6}{12} ) = log_{2}(( \frac{3}{12} ) ^{ - \frac{3}{12} } ) - log_{2}( {( \frac{3}{12}) }^{ \frac{3}{12} } ) - log_{2}( \frac{6}{12} ) ^{ \frac{6}{12} } = log_{2}( ({ \frac{3}{12}) }^{ - \frac{3}{12} } \div ( \frac{3}{12} )^{ \frac{3}{12} } ) - log_{2}( \frac{6}{12} ) ^{ \frac{6}{12} } = log_{2}( {( \frac{3}{12} )}^{ - \frac{3}{12} - \frac{3}{12} } ) - log_{2}( \frac{6}{12} ) ^{ \frac{6}{12} } = log_{2}( \frac{3}{12} ) ^{ - \frac{6}{12} } - log_{2}( \frac{6}{12} ) ^{ \frac{6}{12} } = log_{2}(( \frac{3}{12}) ^{ - \frac{6}{12} } \div {( \frac{6}{12}) }^{ \frac{6}{12} } ) = log_{2}( ({ \frac{3}{12}) }^{ - \frac{6}{12} } \times {2}^{ \frac{6}{12} } ) = log_{2}(( { \frac{1}{4} )}^{ - \frac{1}{2} } \times {2}^{ \frac{1}{2} } ) = log_{2}( {4}^{ \frac{1}{2} } \times {2}^{ \frac{1}{2} } ) = log_{2}(2 \times {2}^{ \frac{1}{2} } ) = log_{2}( {2}^{1 + \frac{1}{2} } ) = log_{2}( {2}^{ \frac{3}{2} } ) = \frac{3}{2}$
Здесь использовались свойства логарифмов и степеней, указанные во вложении.