Найти сумму корней sqrt2x-1 =x-2
2x - 1 = (x - 2)^2
2x - 1 = x^2 - 4x + 4
x^2 - 4x + 4 - 2x + 1 = 0
x^2 - 6x + 5 = 0
D = 36 - 20 = 16
x1 = (6 + 4)/2 = 10/2 = 5
x2 = (6 - 4)/2 = 2/2 = 1
Проверка
√(10 - 1) = 5 - 2
√9 = 3
3 = 3
√(2*1 - 1) ≠ - 1
1 ≠ - 1
Ответ
5