x - 2 \\ 8 - 4x - x + 2 > 0 \\ - 5x + 10 > 0 \\ - 5(x - 2) > 0 \\ x - 2 < 0 \\ x = ( - \infty ..2)" alt="8 - 4x > x - 2 \\ 8 - 4x - x + 2 > 0 \\ - 5x + 10 > 0 \\ - 5(x - 2) > 0 \\ x - 2 < 0 \\ x = ( - \infty ..2)" align="absmiddle" class="latex-formula">
х принадлежит промежутку (-бесконечности;2)