Log(3)(1/x-1)+log(3)(1/x+1)≤log(3)(8x-1)
{1/x-1>0;(1-x)/x>0;x€(0;1)
{1/x+1>0;(1+x)/x>0;x€(-бес;-1)U(0;+бес)
{8x-1>0;8х>1;х>1/8
ОДЗ х€(1/8;1)
log(3)(1/x-1)(1/x+1)≤log(3)(8x-1)
1/x²-1≤8x-1
(1-x²-x²(8x-1))/x²≤0 ; x≠0
x²>0;x≠0
1-x²-8x³+x²≤0
8x³≥1
x³≥(1/2)³
x≥1/2
ответ [1/2;1)