ПОМОГИТЕ ПОЖАЛУЙСТА

2)
$\frac{5x}{4} - x + 1 = ( 3 - x) \frac{1}{2} \\ \frac{5x}{4} - x + 1 = \frac{3}{2} - \frac{x}{2} \\ \frac{5x}{4} - x + \frac{x}{2} = \frac{3}{2} - 1 \\ \frac{5x}{4} - \frac{4x}{4} + \frac{2x}{4} = \frac{3}{2} - \frac{2}{2} \\ \frac{3x}{4} = \frac{1}{2} \\ 3x = 2 \\ x = \frac{2}{3}$
3)
$\frac{3}{2} - ( \frac{x}{4} + \frac{1 - 2x}{6} ) = 2 \\ \frac{3}{2} - ( \frac{x}{4} + \frac{1}{6} - \frac{x}{3} ) = 2 \\ - \frac{x}{4} + \frac{x}{3} = 2 - \frac{3}{2} + \frac{1}{6} \\ - \frac{3x}{12} + \frac{4x}{12} = \frac{12}{6} - \frac{9}{6} + \frac{1}{6} \\ \frac{x}{12} = \frac{4}{6} \\ x = \frac{12 \times 4}{6} = 8$
4)
$\frac{1}{7} \times (5x - 1) - (2 + \frac{x}{2} ) = 0 \\ \frac{5x}{7} - \frac{1}{7} - 2 - \frac{x}{2} = 0 \\ \frac{5x}{7} - \frac{x}{2} = \frac{1}{7} + 2 \\ \frac{10x}{14} - \frac{7x}{14} = \frac{1}{7} + \frac{14}{7} \\ \frac{3x}{14} = \frac{15}{7} \\ 3x = \frac{14 \times 15}{7} = 30 \\ x = 10$