Упростите выражение a^-3,5*(4a^3)^0,3 ПОМОГИТЕ!!!!!!!!!!!!!!
A^-3,5*(4a^3)^0,3 = а^-3.5*4^0.3*а^0.9 = 4^0.3*а^-2.6 = 4^3/10*а^-13/5= =
Решение задания приложено
![{4}^{ \frac{3}{10} } \times \frac{1}{{a}^{ \frac{13}{5} } } = \frac{ {4}^{ \frac{3}{10} } }{ {a}^{ \frac{13}{5} } } = \frac{({2^{2} )}^{ \frac{3}{10} } }{ \sqrt[5]{ {a}^{13} } } = \\ \\ = \frac{ {2}^{ \frac{3}{5} } }{ {a}^{2} \sqrt[5]{ {a}^{ 3} } } = \frac{ \sqrt[5]{ {2}^{3} } }{ {a}^{2} \sqrt[5]{ {a}^{3} } } = \frac{ \sqrt[5]{8} }{ {a}^{2} \sqrt[5]{ {a}^{3} } }](https://tex.z-dn.net/?f=+%7B4%7D%5E%7B+%5Cfrac%7B3%7D%7B10%7D+%7D+%5Ctimes+%5Cfrac%7B1%7D%7B%7Ba%7D%5E%7B+%5Cfrac%7B13%7D%7B5%7D+%7D+%7D+%3D+%5Cfrac%7B+%7B4%7D%5E%7B+%5Cfrac%7B3%7D%7B10%7D+%7D+%7D%7B+%7Ba%7D%5E%7B+%5Cfrac%7B13%7D%7B5%7D+%7D+%7D+%3D+%5Cfrac%7B%28%7B2%5E%7B2%7D+%29%7D%5E%7B+%5Cfrac%7B3%7D%7B10%7D+%7D+%7D%7B+%5Csqrt%5B5%5D%7B+%7Ba%7D%5E%7B13%7D+%7D+%7D+%3D+%5C%5C+%5C%5C+%3D+%5Cfrac%7B+%7B2%7D%5E%7B+%5Cfrac%7B3%7D%7B5%7D+%7D+%7D%7B+%7Ba%7D%5E%7B2%7D+%5Csqrt%5B5%5D%7B+%7Ba%7D%5E%7B+3%7D+%7D+%7D+%3D+%5Cfrac%7B+%5Csqrt%5B5%5D%7B+%7B2%7D%5E%7B3%7D+%7D+%7D%7B+%7Ba%7D%5E%7B2%7D+%5Csqrt%5B5%5D%7B+%7Ba%7D%5E%7B3%7D+%7D+%7D+%3D+%5Cfrac%7B+%5Csqrt%5B5%5D%7B8%7D+%7D%7B+%7Ba%7D%5E%7B2%7D+%5Csqrt%5B5%5D%7B+%7Ba%7D%5E%7B3%7D+%7D+%7D+ "{4}^{ \frac{3}{10} } \times \frac{1}{{a}^{ \frac{13}{5} } } = \frac{ {4}^{ \frac{3}{10} } }{ {a}^{ \frac{13}{5} } } = \frac{({2^{2} )}^{ \frac{3}{10} } }{ \sqrt[5]{ {a}^{13} } } = \\ \\ = \frac{ {2}^{ \frac{3}{5} } }{ {a}^{2} \sqrt[5]{ {a}^{ 3} } } = \frac{ \sqrt[5]{ {2}^{3} } }{ {a}^{2} \sqrt[5]{ {a}^{3} } } = \frac{ \sqrt[5]{8} }{ {a}^{2} \sqrt[5]{ {a}^{3} } }")