Решите задачу:
X=12-y (12-y)*y=35 x=12-y 12y-y²=35 x=12-y y²-12y+35=0 D=144-140=4 y1= (12-2)/2= 5 y2= (12+2)/2= 7 x1= 7 x2= 5 Ответ: (7;5), (5;7)