-25 1/6-(3 1/6+2 1/4):3 3/4*(-3.6)

Решите задачу:

$-25 \frac{1}{6} -(3 \frac{1}{6}+2 \frac{1}{4} )/3 \frac{3}{4} *(-3.6)$
$1)(3 \frac{1}{6}+2 \frac{1}{4} )=5 \frac{1}{6}+ \frac{1}{4} =5 \frac{5}{12}$
$2)5 \frac{5}{12} /3 \frac{3}{4} = \frac{65}{12} / \frac{15}{4} = \frac{65}{12} * \frac{4}{15} = \frac{65}{45} = \frac{13}{9}$
$3) \frac{13}{9} *-3 \frac{6}{10} = \frac{13}{9} *-3 \frac{3}{5} =\frac{13}{9} * -\frac{18}{5} = -\frac{26}{5} =-5 \frac{1}{5}$
$4)-25 \frac{1}{6} -(-5 \frac{1}{5}) =-25 \frac{1}{6} +5 \frac{1}{5}=-19 \frac{29}{30}$