2log2(-x)=1+log2(x+4)

Question

2log2(-x)=1+log2(x+4)

Answer 1

X=-2.
2log2 (-x)=1+log2 (x+4), x€(-4;0)
log 2 ((-x)2)=log2 (2x+8)
x2=2x+8
x2-2x-8=0
X1=4; X2=-2