(х-1)(х+1)(х^2+7х)(х-4)-2=2х

Question

(х-1)(х+1)(х^2+7х)(х-4)-2=2х

Answer 1

(x - 1)(x + 1)(x² + 7x)(x - 4) - 2 = 2x
(x - 1)(x + 1)(x² + 7x)(x - 4) - 2 - 2x = 0
(x - 1)(x + 1)(x² + 7x)(x - 4) - 2(1 + x) = 0
(x + 1)((x - 1)(x² + 7x)(x - 4) - 2) = 0
x1 = -1
(x - 1)(x² + 7x)(x - 4) - 2 = 0
(x² - 5x + 4)(x² + 7x) - 2 = 0
 x^4 + 7x³ - 5x³ - 35x² + 4x² + 28x - 2 = 0
x^4 + 2x³ - 31x² + 28x - 2 = 0
x2 ≈ 0,0718
x3 ≈ 0,9616