Решите, пожалуйста:а²-4/3а+1 × (3а-1)(3а+1)/(3а²+5а-2)

Question

Решите, пожалуйста:
а²-4/3а+1 × (3а-1)(3а+1)/(3а²+5а-2)

Answer 1

(à²-4)/(3a+1)*(3a-1)(3a+1)/(3a²+5a-2)
=(a²-4)(3a-1)/(3a²+5a-2)
3a²+5a-2=0
D=25+24=49=7²
a=(-5±7)/6
a1=-2;a2=1/3
3a²+5a-2=3(a-1/3)(a+2)
(a-2)(a+2)•1/3(a-1/3)/3(a+2)(a-1/3)=
1/3(a-2):3==1/6(a-2)=(a-2)/6