{5(x - 2) - x > 2
{1 - 3(x - 1) < -2
{5x - 10 - x > 2
{1 - 3x + 3 < -2
{4x - 12 > 0
{-3x + 6 < 0
Найдем нули функций y = 4x - 12 и y = -3x + 6
3 \\ x > 2" alt="4x - 12 = 0 \\ - 3x + 6 = 0 \\ \\ 4x = 12 \\ - 3x = - 6 \\ \\ x = 3 \\ x = 2 \\ \\ x > 3 \\ x > 2" align="absmiddle" class="latex-formula">
Ответ: x > 3 или (3; +
)