3y^2+7y- 6 = 3y^2+9y -2y- 6 = 3y(y+3) -2(y+3) = (y+3)(3y-2) D = 7^2 - 4*3* -6 =121 √D = +/- 11 y = 1/(2*3) (-7 +/-11) y1 = -3 y2 = 2/3 (y+3)(y-2/3) = 1/3 (y+3)(3y-2)
ну ты ж не написал