3 5/9 * 1 1/8 - 11 1/5 : 9 1/3 2 1/3α + 1 1/15α = 1 1/6

Решите задачу:

$3 \frac{5}{9} * 1 \frac{1}{8} - 11 \frac{1}{5} : 9 \frac{1}{3} = \frac{32}{9} * \frac{9}{8} - \frac{56}{5} * \frac{3}{28} =4- \frac{6}{5} =2 \frac{4}{5}$

$2 \frac{1}{3} \alpha + 1 \frac{1}{15} \alpha = 1 \frac{1}{6} \\\\ 3 \frac{5+1}{15} \alpha = \frac{7}{6} \\\\ \alpha = \frac{7}{6} : \frac{17}{5} \\\\ \alpha = \frac{35}{102}$