Решите систему способом постановки 2х+6у=28 х-5у=6

Решите задачу:

$\left \{ {2x+6y=28} \atop {x-5y=6}} \right. \\\\ \left \{ {2x+6y=28} \atop {x=5y + 6}} \right. \\\\ \left \{ {10y + 12 +6y=28} \atop {x=5y+6}} \right. \\\\ \left \{ {16y=16} \atop {x=5y+6}} \right. \\\\ \left \{ {y=1} \atop {x=5y+6}} \right. \\\\ \left \{ {y=1} \atop {x=5+6}} \right. \\\\ \left \{ {y=1} \atop {x=11}} \right. \\$