Помогите решить алгебра
(5x+y)/(x-5y) + (5x-y)/(x+5y)÷(x²+y²)/(x²-25y²)= =[(5x+y)(x+5y) + (5x-y)(x-5y)]/(x²+y²)÷(x²+y²)/(x²-25y²)= =[5x²+25xy+5y²+xy+5x²+xy-25xy+5y²](x²-25y²)/(x²+y²)(x²-25y²)= =сокращаем, получаем= =(10x²+10y²)/(x²+y²)=10(x²+y²)/(x²+y²)=10