10[cos3П/4)+isin(3П/4)]:5[cos(П/3)+i sin(П/3)]

Question

10[cos3П/4)+isin(3П/4)]:5[cos(П/3)+i sin(П/3)]

Answer 1

Z1/z2=|z1|/|z2|*(cos(a-b)+isin(a-b))
cos(3П/4-П/3)=cos(5П/12)
sin(3П/4-П/3)=sin(5П/12)
z1/z2=10/5(cos5П/12+isin5П/12)=2(cos5П/12+isin5П/12)