Умоляю!!!!! Помогите Решить !!!дискриминантом подробно 1) 3x²- х = 24 2)4x²=-4-1...

Решите задачу:

$3 {x}^{2} - x = 24 \\ 3 {x}^{2} - x - 24 = 0 \\ a = 3 \: \: \: b = - 1 \: \: \: c = - 24 \\ d = {b}^{2} - 4ac = {( - 1)}^{2} - 4 \times 3 \times ( - 24) = 1 + 240 + 48 = 289 = {17}^{2} \\ x1 = \frac{1 + 17}{2 \times 3} = \frac{18}{6} = 3 \\ x2 = \frac{1 - 17}{6} = \frac{ - 16}{6} = - \frac{8}{3}$

$- 4 {x}^{2} = - 4 - 1 \\ - 4 {x}^{2} + 4 + 1 = 0 \\ - 4 {x}^{2} + 5 = 0 \\ a = - 4 \: \: \: \: b = 0 \: \: \: \: c = 5 \\ d = {0}^{2} - 4 \times ( - 4) \times 5 = 80 ={( 4 \sqrt{5} )}^{2} \\ x1 = \frac{0 + 4 \sqrt{5} }{ - 8} = - \frac{ \sqrt{5} }{2} \\ x2 = \frac{ \sqrt{5} }{2} \\$

$- 25 = 10x + {x}^{2} \\ {x}^{2} + 10x + 25 = 0 \\ d = 100 - 4 \times 1 \times 25 = 0 \\ x1 = x2 = \frac{ - 10 + 0}{2} = - 5$