Решить систему: 2(х+у)=8 14-3(х-у)=5у-х
14-3(x-y)=5y-x 2(x+y)=8 14-3x+3y=5y-x 2x+2y=8 14-3x+3y-5x+x=0 2x+2y=8 14-8x+3y+x=0 x+y=4 x=4-y 14-8(4-x)+3(4+x)+(4+x)=0 14-32+8x+12+3x+4+x=0 12x-2=0 12x=2 x=6 x=6 6=4-y y=4-6 y=-2 x=6y=-2