Помогите пожалуйста))

Решите задачу:

$\left \{ {{3(x-5)-1=-2y} \atop {3(x-y)-7y=-4}} \right. =\ \textgreater \ \left \{ {{3x-15-1=-2y} \atop {3x-3y-7y=-4}} \right. =\ \textgreater \ \left \{ {{3x-16=-2y} \atop {3x-10y=-4}} \right. =\ \textgreater \ \newline =\ \textgreater \ \left \{ {{3x=-2y+16} \atop {-2y+16-10y=-4}} \right. =\ \textgreater \ \left \{ {{3x=-2y+16} \atop {-12y=-20}} \right. =\ \textgreater \ \left \{ {{3x=-2y+16} \atop {y=\frac{20}{12}=\frac{5}{3}}} \right. =\ \textgreater \ \newline \left \{ {{3x=\frac{-2*5}{3}+16} \atop {y=\frac{5}{3}}} \right. = \ \textgreater \ \newline \left \{ {{3x=\frac{38}{3}} \atop {y=\frac{5}{3}}} \right. =\ \textgreater \$ $\left \{ {{3x=\frac{38}{3}} \atop {y=\frac{5}{3}}} \right. =\ \textgreater \ x= 38/9$