3\\\\log_2\frac{x+3}{x-3}=log_22\\\\\frac{x+3}{x-3}=2\\\\\frac{x+3-2x+6}{x-3}=0\\\\\frac{-x+9}{x-3}=0\\\\-x+9=0\; ,\; x=9" alt="log_2(x+3)-log_2(x-3)=1\; ,\; ODZ:x>3\\\\log_2\frac{x+3}{x-3}=log_22\\\\\frac{x+3}{x-3}=2\\\\\frac{x+3-2x+6}{x-3}=0\\\\\frac{-x+9}{x-3}=0\\\\-x+9=0\; ,\; x=9" align="absmiddle" class="latex-formula">