Решить систему уравнений
X = 2 - y^2 x^2 = 4 - 4y^2 + y^4 2y^2 + 4 - 4y^2 + y^4 = 3 y^4 - 2y^2 + 1 = 0 ( y^2 - 1 )^2 = 0 y^2 - 1 = 0 y^2 = 1 y1 = 1 y2 = - 1 x1 = 2 - 1 = 1 x2 = 2 - 1 = 1 Ответ ( 1 ; - 1 ) ; ( 1 ; 1 )