1 \\ x+1 \neq 1 \\ x \neq 0 \\ \left \{ {{x+1>0,} \atop {5-x>0;}} \right. \left \{ {{x>-1,} \atop {x<5.}} \right. " alt="log_{x+1}5-x>1 \\ x+1 \neq 1 \\ x \neq 0 \\ \left \{ {{x+1>0,} \atop {5-x>0;}} \right. \left \{ {{x>-1,} \atop {x<5.}} \right. " align="absmiddle" class="latex-formula">
x∈(-1; 5)
log_{x+1}x+1 \\ 5-x>x+1 \\ -2x>-4 \\ x<2" alt="log_{x+1}5-x>log_{x+1}x+1 \\ 5-x>x+1 \\ -2x>-4 \\ x<2" align="absmiddle" class="latex-formula">
x∈(-1; 2)
Ответ: x∈(-1; 2).