АЛГЕБРА 8 КЛАСС. ПОЖАЛУЙСТА С РЕШЕНИЕМ

Question 1

Question 2

1) $\frac{12 \frac{4}{5}*3 \frac{3}{4}-4 \frac{4}{11}*4 \frac{1}{8} }{11 \frac{2}{3}:2 \frac{4}{7} } = \frac{ \frac{64*15}{5*4} - \frac{48*33}{11*8} }{ \frac{35*7}{3*18} }= \frac{48-18}{ \frac{245}{54} }= 30:245:54= \frac{324}{49}=6 \frac{30}{49}$

2) $\frac{28 \frac{4}{5}: 13\frac{5}{7} +6 \frac{3}{5}: \frac{2}{3}}{1 \frac{11}{16}:2 \frac{1}{4} }= \frac{ \frac{144}{5}* \frac{1}{13}* \frac{5}{7}+ \frac{33}{5}* \frac{3}{2}}{ \frac{27}{16}: \frac{9}{4}}= \frac{144* \frac{1}{13}* \frac{1}{7}+ \frac{99}{10}}{ \frac{27}{16}* \frac{4}{9} }= \frac{ \frac{144}{91}+ \frac{99}{10}}{ \frac{3}{4} } =$ $10449:910:3:4= \frac{6966}{455} =15 \frac{141}{455}$

3) $\frac{2 \frac{3}{8}: \frac{3}{4}+24 \frac{7}{9} }{7 \frac{1}{8}-157 \frac{4}{5}:24}= \frac{ \frac{19}{8}* \frac{4}{3}+ \frac{223}{9} }{ \frac{57}{8}- \frac{789}{5}* \frac{1}{24}}= \frac{ \frac{19}{2}* \frac{1}{3}+ \frac{223}{9}}{ \frac{57}{8}- \frac{263}{5}* \frac{1}{8} }= \frac{ \frac{19}{6}+ \frac{223}{9} }{ \frac{57}{8}- \frac{263}{40}}=503:18:11:20=$ $\frac{5030}{99} = 50 \frac{80}{99}$

4) $\frac{(1 \frac{1}{2}+2 \frac{2}{3}+3 \frac{3}{4})*3 \frac{3}{5} }{14-15 \frac{1}{8}:2 \frac{1}{5} }= \frac{((1+2+3)+( \frac{1}{2}+ \frac{2}{3}+ \frac{3}{4}))* \frac{18}{5} }{14- \frac{121}{8}: \frac{11}{5}}= \frac{(6+ \frac{23}{12})* \frac{18}{5} }{14- \frac{11}{8}*5 }= \frac{(6+1+ \frac{11}{12})* \frac{18}{5} }{14- \frac{55}{8} }$ $\frac{(7+ \frac{11}{12})* \frac{18}{5}}{ \frac{57}{8} }= \frac{ \frac{19}{12}* \frac{18}{5} }{ \frac{57}{8} } = \frac{ \frac{57}{2} }{ \frac{57}{8} }=4$

Question 3

Скоро допишу остальное...