SinA = a/b
cosA = b/c
tgA = a/b
sinB = b/c = cosA
cosB = a/c = sinA
tgB = b/a
Сначала по т.Пифагора находим недостающую сторону, потом считаем:
1) с = √(61)
sinA = cosB = 5/√(61)
cosA = sinB = 6/√(61)
tgA = 5/6
tgB = 6/5
2) b = 6
sinA = cosB = 8/10 = 4/5
cosA = sinB = 6/10 = 3/5
tgA = 8/6 = 4/3
tgB = 6/8 = 3/4
3) c = √(313)
sinA = cosB = 12/√(313)
cosA = sinB = 13/√(313)
tgA = 12/13
tgB = 13/12
4) a = √(175)
sinA = cosB = √(175)/20
cosA = sinB = 15/20 = 3/4
tgA = √(175)/15
tgB = 15/√(175)
5) b = √(135)
sinA = cosB = 11/16
cosB = sinA = √(135)/16
tgA = 11/√(135)
tgB = √(135)/11