Sin5x – sinx – cos3x = 0
sin5x – sinx = 2sin2x • cos3x
2sin2x • cos3x – cos3x = 0
cos3x • (2sin2x – 1) = 0
cos3x = 2sin2x – 1=0
x = πu ÷ 6 + πu/3 • k
х= πu ÷ 12 +пи/2 • k
ИЛИ
cos3x + sin5x – sinx = 2sin2xcos3x + cos3x = cos3x • (2sin2x + 1)
cos3x = 0 2sin2x = – 1
x= ± – arccos3 + 2Пn sin2x = – 1/2
2x = (– 1) k + 1 • П ÷ 6 + Пk ÷ 2
x = (– 1) k + 1 • П ÷ 12 + Пk ÷ 2