1) домножаем на 2
x^2+1-2x=4
x^2-2x-3=0
D=(-2)^2+4*3=4+12=16=4^2
x1=2+4/2=3; x2=2-4/2=-1
Ответ: 3; -1
2) а) (4m^2+12m+9)/(2m^2-m-6)=(2m+3)^2/2(m-3)(m+1,5)=(2m+3)^2/(m-3)(2m+3)=(2m+3)/m-3
б) (a^3+a^2-a-1)/(a^2+2a+1)=(a(a^2-1)+(a^2-1))/(a+1)^2=(a+1)(a^2-1)/(a+1)^2=(a^2-1)/(a+1)=(a+1)(a-1)/(a+1)=a-1