Найдите значение производной функции
Y=cos(4x-π/6) x0=π/12 y'=-4sin(4x-π/6) y'(x0)=-4sin(4π/12-π/6) = -4sinπ/6=-2 y=ln(3-x) x0=-2 y'=-1/ln(3-x) x0=-2 y'=-1/ln5 y=e^(3x-1) x0=1/3 y'=3*e^0=3 y=√(3x+10) x0=2 y'=3/2√(3x+10) x0=2 y'=3/2*4=3/8