\left \{ {{5 ^{2x+y}=125 } \atop {4 ^{(x-y)} ^{2} =1 }} \right.

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\left \{ {{5 ^{2x+y}=125 } \atop {4 ^{(x-y)} ^{2} =1 }} \right.
\left \{ {{5 ^{2x+y}=125 } \atop {4 ^{(x-y)} ^{2} =1 }} \right.


Алгебра (477 баллов) | 79 просмотров
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решить систему?

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x=y=1

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Решите задачу:

\left \{ {{5 ^{2x+y}=125 } \atop {4 ^{(x-y)} ^{2} =1 }} \right. \\\\ \left \{ {{5 ^{2x+y}=5^3 } \atop {4 ^{(x-y)} ^{2} =4^0 }} \right. \\\\ \left \{ {{2x+y=3 } \atop {(x-y)} ^{2} =0 }} \right. \\\\ \left \{ {{2x+y=3 } \atop {x-y=0 }} \right. \\\\ \left \{ {{2x+y=3 } \atop {3x=3 }} \right. \\\\ \left \{ {{2x+y=3 } \atop {x=1 }} \right. \\\\ \left \{ {{2+y=3 } \atop {x=1 }} \right. \\\\ \left \{ {{y=1 } \atop {x=1 }} \right.
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