Решите пожалуйста:(а-3)^2= (х+3)^2= (х+у)^2= (х-у)^2= (2х-3)^2= (2у-4)^2= (3-х)(9+3х+х^2)= (6+х)(36-6х+х^3)=
(a – 3)² = a² - 6a + 9
(x + 3)² = x² + 6x +9
(x + y)² = x² + 2xy + y²
(x – y)² = x² - 2xy + y²
(2x – 3)² = 4x² - 12x +9
(2y – 4)² = 4y² - 16y + 16
(3 – x)(9 + 3x + x²) = 27 - x³
(6 + x)(36 – 6x + x³) = x⁴ + 6x³ - 6x² + 216
1 x^{2} +6x +9 1a^2-6a+92 x^{2} +2xy+y^2 3 x^2-2xy+y^2 4 4x^2-12x+9 5 4y^2 -16y+16 6 27-x^3 7 6^3+x^3