Помогите решить пожалуйста

1)

$[tex]4y + 10 \geqslant 2(1 - y) + 24 = 4y + 10 \geqslant 2 - 2y + 24 = 4y + 10 \geqslant 26 - 2y = 4y + 2y \geqslant 26 - 10 = 6y \geqslant 16 = y \geqslant \frac{8}{3} = 2.7$

2)

$29x + 4 \times \frac{1}{4} \geqslant 332 + 3 \frac{1}{3} = 29x + 1 \geqslant 332 + 1 = 29x \geqslant 332 = x \geqslant \frac{332}{29} = 11.5$

3)

0.4 = 1.2x > 0.4 - 2 = 1.2x > - 1.6 = x > - \frac{4}{3} = 1.4 " alt="1.2x + 2 > 0.4 = 1.2x > 0.4 - 2 = 1.2x > - 1.6 = x > - \frac{4}{3} = 1.4 " align="absmiddle" class="latex-formula">
4)
8 = - \frac{1}{2} y > 0 = - y > 0 = y < 0" alt="8 - \frac{1}{2} y > 8 = - \frac{1}{2} y > 0 = - y > 0 = y < 0" align="absmiddle" class="latex-formula">