Решите уравнение 1) 3+(х-7)²=(х-2)(х+2) 2) (х+6)²-(х-5)(х+5)=73

Question

Решите уравнение
1) 3+(х-7)²=(х-2)(х+2)
2) (х+6)²-(х-5)(х+5)=73

Answer 1

3 + (x - 7)² = (x - 2)(x + 2)
3 + x² - 14x + 49 = x² - 4
3 - 14x + 49 = -4
51 - 14x = -4
-14x = -4 - 52
-14x = -56
x = 4

(x + 6)² - (x - 5)(x + 5) = 73
x² + 12x + 36 - (x² - 25) = 73
x² - 12x + 36 - x² + 25 = 73
12x + 61 = 73
12x = 73 - 61
12x = 12
x = 1

Comments

-4-52=-56

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отпечатка спасибо