Прошу помощи в математике (11 класс). Тема: "Обобщение понятия о показатели степени"....

Решите задачу:

$1.\\ a)(121^{\frac12}+128^{\frac57}-81^{1\frac14})*125^{-\frac13}=(11^{2*\frac12}+2^{7*\frac57}-3^{4*\frac54})*5^{3*(-\frac13)}=\\ =(11+2^5-3^5)*5^{-1}=(11+32-243)*\frac15=-\frac{200}5=-40\\ \\ b)...=\frac{32^{0.7*0.6}*64^{\frac13*0.6}}{8^{0.1}}=\frac{32^{0.42}*64^{\frac15}}{8^{0.1}}=\frac{32^{\frac{21}{50}}*64^{\frac15}}{8^{\frac1{10}}}=\frac{2^{5*\frac{21}{50}}*2^{6*\frac15}}{2^{3*\frac1{10}}}=\\$
$=\frac{2^{\frac{21}{10}}*2^{\frac65}}{2^{\frac3{10}}}=2^{\frac{21}{10}+\frac65-\frac3{10}}=2^{\frac{21+12-3}{10}}=2^{\frac{30}{10}}=2^3=8$

$2.\\ a)(81a^{-8})^{-\frac34}=3^{4*(-\frac34)}*a^{-8*(-\frac34)}=3^{-3}*a^6=\frac{a^6}{3^3}=\frac{a^6}{27}\\ \\ b)...=\frac{x^{\frac25+\frac1{10}}}{x^{-\frac32}}=\frac{x^{\frac3{10}}}{x^{-\frac32}}=x^{\frac3{10}+\frac32}=x^{\frac{18}{10}}=x^{1.8}$