(x-3)^2=4 (x+12)^3=27

Question

(x-3)^2=4
(x+12)^3=27

Answer 1

1) (x-3)^2-2^2=0
(x-3-2)(x-3+2)=0
(x-5)(x-1)=0
x=5
x=1
Ответ: 1; 5
2)(x+12)^3=27
x+12=3
x=3-12=-9
Ответ: -9

Answer 2

1)2х-6=4
2х=10
х=5
2)3х+36=27
3х=-9
х=-3