(x+2)^4+(z+2)^2-12=0

Question

(x+2)^4+(z+2)^2-12=0

Answer 1

(x+2)^4 + (x+2)^2 - 12 = 0
(x+2)^2 = m
m^2 + m - 12 = 0
D= b^2 - 4ac = 1 - 4 * 1 * (-12) = 1 + 48 = 49
m1 = (-b + √49) / 2a = (-1 + 7)/ 2 * 1 = 6/2=3
m2 = (-b - √49) / 2a = (-1-7)/2 = -8/2 = -4
(x+2)^2 = 3
x^2 + 4x + 4 -3 =0
x^2+4x+1=0
D=16-4=12
x1 = (-4+√12)/2 = (2(-2+√3))/2 = -2+√3
x2 = -2-√3