Решите уравнение (2х-7)(х+1)+3(4х-1)(4х+1)=2(5х-2)^2-53

Решение:
$(2x - 7)(x + 1) + 3(4x - 1)(4x + 1) = 2(5x - 2 {)}^{2} - 53 \\ 2 {x}^{2} + 2x - 7x - 7 + 3(16 {x}^{2} - 1) = 2(25 {x}^{2} - 20x + 4) - 53 \\ 2 {x}^{2} - 5x - 7+ 48 {x}^{2} - 3 = 50 {x}^{2} - 40x + 8 - 53 \\ 50 {x}^{2} - 5x -10 = 50 {x}^{2} - 4 0x - 45 \\ 40x - 5x = - 45 + 10 \\ 35x = - 35 \\ x = - \frac{35}{35} \\ x = - 1$