(x-17)(x+2x-40)=0 ...Решите пожалуйста)
(x-17)=0 или (x+2x-40)=0
х=17 3х=40
х=40/3
(x-17)(x+2x-40)=0
x^2+2x^2-40x-17x-34x+680=0
3x^2-91x+680=0
3x2 - 91x + 680 = 0 D = b2 - 4ac D = 8281 - 8160 = 121 = 11^2
x1,2 = -b ± √D/2a x1 = 91 + 11/6 = 102/6 = 17 x2 = 91 - 11/6 = 80/6 = 40/3 Ответ: x1 = 17 ; x2 = 40/3