Помогите срочно пж 7y-4(3y+5)=2-3(4y-9)

Question

Помогите срочно пж 7y-4(3y+5)=2-3(4y-9)

Answer 1

7y-4(3y+5)=2-3(4y-9)
7y-12y-20=2-12y+27
7y-12y+12y=2+20+27
7y=49
y=7

Comments

спс

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незачто

Answer 2

7y-4(3y+5)=2-3(4y-9)
7y-12y-20=2-12y+27
7y=49
y=49:7
y=7